Simple Uniform Acceleration Problem

AI Thread Summary
A bicycle accelerates from rest, covering 16 meters in 4 seconds, with a total mass of 90 kg. The average acceleration can be calculated using the equation x = ut + 0.5at^2, leading to the correct average acceleration of 2 m/s². The initial calculations incorrectly derived average velocity instead of acceleration, highlighting the importance of using the right formulas. The average velocity is 4 m/s, but this does not directly yield average acceleration without considering the change in velocity. The discussion emphasizes the need to apply the correct equations for uniform acceleration problems.
TheKovac
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Homework Statement


A bicycles accelerates from rest, covering 16 metres in 4 seconds. The total mass of the bicycle and its rider it 90kg. What is its average acceleration during this time?

Homework Equations


x = ut + 0.5at^2
v=xt
a=vt

The Attempt at a Solution


v = x/t
v = (16)/(4)
v = 4 m/s

F = mv/t
F = (90)(4)/4
Fnet = 90N

Fnet = ma
90 = 90a
A= 1 m/s^2 <--WRONG! - How?
A=2ms <--- RIGHT
 
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TheKovac said:

Homework Statement


A bicycles accelerates from rest, covering 16 metres in 4 seconds. The total mass of the bicycle and its rider it 90kg. What is its average acceleration during this time?

Homework Equations


x = ut + 0.5at^2
v=xt
a=vt

The Attempt at a Solution


v = x/t
v = (16)/(4)
v = 4 m/s

F = mv/t
F = (90)(4)/4
Fnet = 90N

Fnet = ma
90 = 90a
A= 1 m/s^2 <--WRONG! - How?
A=2ms <--- RIGHT

Why didn't you just use x = ut + 0.5at^2 ?
 
TheKovac said:

Homework Statement


A bicycles accelerates from rest, covering 16 metres in 4 seconds. The total mass of the bicycle and its rider it 90kg. What is its average acceleration during this time?

Homework Equations


x = ut + 0.5at^2
v=xt
a=vt

Your equations are not quite right here and they are leading to some problems. The second and third equations need to be:

<br /> v_{\rm average} = \frac{x_f-x_i}{\Delta t}<br />

<br /> a_{\rm average} = \frac{v_f-v_i}{\Delta t}<br />

The Attempt at a Solution


v = x/t
v = (16)/(4)
v = 4 m/s

This quantity you have calculated is the average velocity over the whole time period.

F = mv/t
F = (90)(4)/4
Fnet = 90N

Dividing the average velocity by the time here does not give you the average acceleration; you would need the beginning and ending velocities.


However, if you use your first equation:

<br /> \Delta x = v_0 t + \frac{1}{2} a t^2<br />

you should get the right answer immediately.
 
You can't use a constant acceleration law - The question never said that the acceleration was constant, it wanted you to find the average acceleration.
Also:
average velocity = displacement / time interval
average acceleration = change in velocity / time interval

16/4 = average velocity
 
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