Simple Work and Energy question

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SUMMARY

The discussion centers on calculating the force and work done by a helicopter with mass M accelerating upward at 0.10g. The correct force required is F = 1.10Mg, which accounts for both the weight of the helicopter and the additional acceleration. Consequently, the work done as the helicopter moves a distance h upward is W = 1.10Mgh. The discrepancy arises from neglecting the weight of the helicopter in the initial calculations.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of work-energy principles (W=Fx)
  • Basic concepts of gravitational force (weight = mg)
  • Familiarity with acceleration due to gravity (g)
NEXT STEPS
  • Study the derivation of force calculations in dynamics, particularly for objects under acceleration.
  • Explore the relationship between work and energy in mechanical systems.
  • Review examples of forces acting on objects in gravitational fields.
  • Investigate common misconceptions in physics related to force and acceleration.
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of force and work in dynamic systems.

pinkerpikachu
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A) the force required to give a helicopter of a mass M an acceleration of .10g upward.
B) Find the work done by this force as the helicopter moves a distance of h upward

I'm not incompetent or totally clueless about this.I know that F=ma and W=Fx

So, my solutions:

a) F=ma
F= .10Mg

b) W=Fx
W=.10Mgh


But the answer in the back of my book has a) 1.10Mg B) 1.10Mgh so either I'm missing some crucial step, or my book has a typo

help please?
 
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pinkerpikachu said:
A) the force required to give a helicopter of a mass M an acceleration of .10g upward.
B) Find the work done by this force as the helicopter moves a distance of h upward

I'm not incompetent or totally clueless about this.I know that F=ma and W=Fx

So, my solutions:

a) F=ma
F= .10Mg

b) W=Fx
W=.10Mgh


But the answer in the back of my book has a) 1.10Mg B) 1.10Mgh so either I'm missing some crucial step, or my book has a typo

help please?

Unfortunately you forgot that the Helicopter has a weight of m*g.
To accelerate it another .1g means that it must overcome the original m*g and then add the extra .1*m*g.
 

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