How Is Power Calculated in a Simple Work-Energy Problem?

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In summary, using the given information, we can calculate the acceleration of the object to be 2.5 m/s/s. Then, using the displacement equation, we find that the object has traveled 5m. The work done on the object is 25 J and the power is 12.5 W. However, none of the given answer choices match this calculation, indicating a possible error in the formula for power.
  • #1
StonieJ
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A force of 5N acts on a 2 kg object that starts from rest. When the force has been acting for 2 s, the rate at which it is doing work is:

Here's how I tried to solve it.

Solve for acceleration, which I assumed was constant.

Code:
a = F/m = 5N / 2kg = 2.5 m/s/s


Then use the displacement equation to find the distance traveled.

Code:
x = xo + (vo)(t) + (1/2)(a)(t^2) 
x = 0 + 0 + (1/2)(2.5 m/s/s)(2s)^2 
x = 5m 

Work = F * x = 5N * 5m = 25 J 

Power = Work / t = 25J / 2s = 12.5 W
However, the only possible answer choices are:
a) 5W b) 10W c) 25W d) 50W e) 75W

Where am I screwing up?
 
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  • #2
[tex]P=\frac{dW}{dt}[/tex]
[tex]P=\frac{d(Fs)}{dt}[/tex]
[tex]P=F\frac{ds}{dt}[/tex]
[tex]P=F\frac{d(ut+\frac{1}{2}at^2)}{dt}[/tex]
[tex]P=F*(u+at)[/tex]
[tex]P=5*(2.5*2)[/tex]
[tex]P=25\ W[/tex]
You formula for power can't be used in this case because P is not constant for P depends on how long the force acts on the object.
 
  • #3


You are not screwing up, your calculations are correct. The only issue is that the answer choices provided are not all correct. The correct answer should be 12.5W, which is not listed as an option. This could be a mistake or error in the question or answer choices. It is always important to double check your calculations and compare them to the given answer choices to ensure accuracy. In this case, your calculations are correct and the given answer choices are incorrect.
 

Related to How Is Power Calculated in a Simple Work-Energy Problem?

1)

What is a simple work-energy problem?

A simple work-energy problem involves calculating the amount of work done on an object or the amount of energy possessed by an object as a result of a force acting on it. This type of problem often involves the use of the work-energy theorem, which states that the net work done on an object is equal to the change in its kinetic energy.

2)

How do you solve a simple work-energy problem?

To solve a simple work-energy problem, you first need to identify the forces acting on the object and determine the work done by each force. Then, you can use the work-energy theorem to calculate the change in kinetic energy and solve for the unknown variable.

3)

What is the formula for calculating work?

The formula for calculating work is W = Fd cosθ, where W is work, F is the force applied, d is the displacement of the object, and θ is the angle between the force and displacement vectors. This formula applies for both simple and complex work-energy problems.

4)

Can you have negative work or negative energy in a simple work-energy problem?

Yes, it is possible to have negative work or energy in a simple work-energy problem. This occurs when the force and displacement vectors are in opposite directions, resulting in a negative value for work. Negative energy can also occur if the kinetic energy of the object decreases due to work being done on it by a force.

5)

What are some real-life applications of simple work-energy problems?

Simple work-energy problems have many real-life applications, such as calculating the energy needed to lift an object, the work done by a car's engine to accelerate, or the energy transferred during a collision. These types of problems are also commonly used in engineering and physics to analyze the motion and forces involved in various systems.

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