Simplify each of this following surd

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The discussion focuses on simplifying the expression 3∜2 - ∜(2/81) + ∜32 - ∜162. Participants clarify that 32 - 162 equals -130 and emphasize the importance of correctly applying the properties of surds, noting that the difference of fourth roots cannot be simplified as the root of a difference. The correct simplification of ∜(2/81) is identified as √[4]2/3, leveraging the fact that 81 equals 3^4. Additionally, factoring 162 into its prime components is suggested for further simplification. The conversation highlights common pitfalls in manipulating surds and the need for careful calculations.
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Homework Statement


3∜2 - ∜(2/81) + ∜32 - ∜162

Homework Equations

The Attempt at a Solution


3∜2 - ∜(2/81) - ∜130
3∜2 – ∜2/3 - ∜130
exactly when i tried to calculate, i got problem with the next of this calculating, i confused. Can anybody help me for do the next of this calculating??[/B]
 
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Where does the 130 come from? That looks like an incorrect transformation.

Did you split the numbers in the square roots into their prime factors?
 
oh i wrong, i mean 3∜2 - ∜(2/81) - ∜130
3∜2 – ∜2/3 - ∜130, and then the 130 come from 32-162
 
jonathan22 said:

Homework Statement


3∜2 - ∜(2/81) + ∜32 - ∜162

jonathan22 said:
oh i wrong, i mean 3∜2 - ∜(2/81) - ∜130
3∜2 – ∜2/3 - ∜130, and then the 130 come from 32-162

First off, 32 - 162 = -130. More importantly, ##\sqrt[4]{a} - \sqrt[4]{b} \ne \sqrt[4]{a - b}##.
As already mentioned simpligy ##\sqrt[4]{162}## by factoring 162 into its prime factors.
 
ok, but how to solve ∜(2/81)?
 
That part was right. $$ \frac{\sqrt[4]2}{3}$$
 
It helps to know that 81= 3^4 and 162= 2(3^4).
 
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