Simplify the following equation [Complex Numbers]

jcurl
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Homework Statement


I'm in differential equations right now and we are about to start Laplace Transforms. Our homework is over complex numbers:

Simplify the following equation:
1+cos(\theta)+cos(2\theta)+cos(3\theta)+...+cos(n\theta)


Homework Equations





The Attempt at a Solution


I have no idea where to start. My only guess would be to do this: \sum_{i=0}^n cos(n\theta) but I feel like that's way to easy and not what he is asking for.
 
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If you are going to start Laplace transforms, you likely know about complex numbers. cos(n*theta) is the real part of exp(i*n*theta), yes? Can you relate your question to a geometric series?
 
Dick said:
If you are going to start Laplace transforms, you likely know about complex numbers. cos(n*theta) is the real part of exp(i*n*theta), yes? Can you relate your question to a geometric series?

That's what I was thinking, but I'm not sure how to only get the cos value. Since e^{i\theta} = cos(\theta) + isin(\theta)
 
Hint: scroll up and read Dick's post carefully.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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