Simplifying a trigonometric product

Manni
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Was just double checking if we can simplify this in the following way,

∫ sinx * √(1 + cos2x) dx = ∫ sinx * (1 + cosx) dx
 
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Manni said:
Was just double checking if we can simplify this in the following way,

∫ sinx * √(1 + cos2x) dx = ∫ sinx * (1 + cosx) dx
No.

Is \sqrt{3^2+4^2}=7\ ? No !

\sqrt{3^2+4^2}=\sqrt{25}=5\ ..

To solve that integral, use substitution .

Ask your self, what's the derivative of cos(x) ?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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