Simplifying transfer function block diagram

AI Thread Summary
The discussion revolves around the need to simplify a block diagram for a homework assignment, with an image provided for reference. Participants express frustration over the image's unreadability, emphasizing the importance of clear visuals for problem-solving. Suggestions are made to upload a larger, more legible version of the image to facilitate assistance. One user provides a link to a clearer version of the diagram. The conversation highlights the necessity of accessible images in technical discussions to enhance understanding.
Scott77
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Homework Statement


Simplify the block diagram. I uploaded a single image as it's the easiest way to do this problem.

Homework Equations


None at this stage.

The Attempt at a Solution


Please see the image.
simplify.jpg
 
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Scott77 said:

Homework Statement


Simplify the block diagram. I uploaded a single image as it's the easiest way to do this problem.

Homework Equations


None at this stage.

The Attempt at a Solution


Please see the image.
View attachment 211294

The posted image is virtually unreadable.
 
Ray Vickson said:
The posted image is virtually unreadable.
I agree.
While we generally discourage images in posts, in this case an image is very helpful.

Please post an image that is large enough so that we can read it.
 
This is approaches being readable. Use the Image icon in blue banner just a text box used to make a post.
media%2F6cf%2F6cf3d73b-49e7-4ad5-bdca-0de8630e5144%2FphpEjXFYE.png
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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