Single Phase Transformer: Short Circuit Experiment Results and Calculations

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The discussion revolves around a short circuit experiment conducted on a single-phase transformer with nominal ratings of 10kV/0.4kV and 100kVA. Participants seek assistance in calculating the electric current and power when the higher side is fed with 400V, as well as the necessary feeding voltage to achieve 1kW power when the lower side is shorted. There is a focus on using the equation P=V.I.cosφ for calculations, but confusion arises regarding the application of this formula and the interpretation of results. Clarifications are requested on the calculations performed, particularly concerning the impedance derived from the initial test. The conversation highlights the need for accurate terminology and understanding of electrical principles in transformer operations.
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hi guys,
this is a question from an exam about a single phaze transformer and it goes like this, I am sorry for the bad translation in some parts i couldn't find the correct terms:
A single phaze transformer is given with nominal data of - 10k/0/4 kV/kV , 100kVA
A short circuit experiement was done when the low side of the voltage is shorted and the other side (higher side of the voltage) is fed with 500V. The following results came: I=10A , P=1kW

A. what will be the electric current flow and power in the short circuit experiement if the higer side of the voltafe was fed with 400V?
B. we short the higher side of the voltage and feed the transformer on the lower side of the voltage. what should be the feeding voltage in this case to the power will be 1kW? what will be the current?

I gave it a try but it dosent look too succefull could you help me out please?
Thank you for reading!
 
Last edited:
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Can you edit the subject line, and change "transistor" to "transformer"?

Is this a 10kV to 4kV transformer?
 


i tried editing the title right after i posted it and couldn't change it

its 10k to 0.4k
 


I think you will need to show your calculations for the s/c test using 500v, before anyone can say whether you are doing something wrong.

A useful equation is: P=V.I.cos\phi
 
Last edited:


You have Zk=Vk/Ik = 1000 ohms
Why isn't it 500v / 10 Amp?

Where did you find the equation: V=V(1-kLuk.cos(phi - uL))
and, more to the point, do you actually use it?

I can't discern some of your subscripts. What does the subscript "k" stand for?
 

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