Singularities of a Complex Function

ThLiOp
Messages
8
Reaction score
0

Homework Statement



What are the region of validity of the following?

1/[z2(z3+2)] = 1/z3 - 1/(6z) +4/z10

Homework Equations

The Attempt at a Solution



Knowing that this is the expansion around z=0, I am trying to find the singularities of the complex function.

Which is when z2(z3+2) = 0

I have z = 0, then (z3+2) = 0

(z3+2) = 0

z3 = -2 = r3ei3θ

In order to find r, would I take the absolute value of z3?

r = |z3| = |-2| = sqrt[(-2)2] = 2?
 
Physics news on Phys.org
ThLiOp said:
r = |z3|
I don't think that's what you meant. Try again.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
2
Views
2K
Replies
2
Views
3K
Replies
2
Views
2K
Replies
1
Views
2K
Replies
15
Views
3K
Replies
2
Views
2K
Replies
4
Views
3K
Replies
2
Views
5K
Back
Top