Sinusoidal current phase angle question

AI Thread Summary
The discussion revolves around determining the phase angle of the sinusoidal current i2(t), given that i1(t) has a phase angle of 60 degrees and leads i2(t) by 0.25 ms. Both currents operate at a frequency of 500 Hz, which translates to a period of 2 ms. The time difference of 0.25 ms represents an eighth of the full wave period. By calculating this fraction, the phase angle of i2(t) can be deduced as 60 degrees minus 45 degrees, resulting in a phase angle of 15 degrees. The thread emphasizes the importance of understanding wave periods to solve phase angle problems effectively.
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Homework Statement



The sinusoidal current i1(t) has a phase angle of 60 degrees. Furthermore, i2(t) attains its positive peak 0.25ms earlier than the current in i2(t) (i.e i1(t) leads i2(t)). Both currents have a frequency of 500 Hz. Determine the phase angle of i2(t)


Homework Equations



I think we would use this equation: v1(t) = V1cos(wt + theta1)

The Attempt at a Solution



I just can't find a formula in t he book that adds both currents in order to obtain the missing phase angle. Much help is appreciated!
 
Physics news on Phys.org
You won't need a 'canned' formula for this problem. The first thing to determine is what fraction of a whole wave period does 0.25ms represent? What's the period of the sinusoids?
 

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