Finding Function Values on a Graph: f(30) and f(-14) Explained

AI Thread Summary
The discussion focuses on finding the function values f(30) and f(-14) from a periodic graph of y=f(x). Participants note that the graph has a periodicity of 4, which means f(x+4)=f(x). This periodicity allows for the calculation of function values at different points by identifying equivalent x-values within the period. The values can be derived by recognizing patterns in the graph. Understanding the periodic nature is essential for justifying the answers for f(30) and f(-14).
Sonny18n
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1. Homework Statement

A graph of y=f(x) is shown. Find the following function values and justify your answers.

f(30)=
f(-14)=

Homework Equations

The Attempt at a Solution


I know the graph is periodic, I know it's max and min, and I know it's amplitude because of that. But I don't know what the 30 or -14 is supposed to mean to me or how I'm suppose to "justify" my answer[/B]
 
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Sonny18n said:
View attachment 80886 1. Homework Statement
A graph of y=f(x) is shown. Find the following function values and justify your answers.

f(30)=
f(-14)=

Homework Equations

The Attempt at a Solution


I know the graph is periodic, I know it's max and min, and I know it's amplitude because of that. But I don't know what the 30 or -14 is supposed to mean to me or how I'm suppose to "justify" my answer[/B]

It looks to me like what you are supposed to conclude from the graph is that f(x+4)=f(x). That's periodic. So f(-14)=f(-10)=f(-6)=f(-2). The last value you can read off from the graph. Patterns like that.
 
f(30) and f(-14) are the values of the function calculated in x=30 and x=-14.
You said that the graph is periodic, so it means that the graph repeat itself with perod 5.
now you should obtain the two values.
 
Yes, Dick is right, the period is 4
 
Pierce610 said:
Yes, Dick is right, the period is 4
(It is possible for you to Edit post #3. )
 
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Now no more; I'll do it in future if I should realize in time to have to correct my post
 
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I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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