I have to sketch the following function: y=x(lnx)^3 The ln scares me a bit... I have found the derivative of the function as 3(lnx)^2, and when making that equal to zero I got an anwer of around 0.7 if i remember correctly. This I guess is my critical number??? Then the second derivative is 6/x(lnx). I really am not sure if Im doing this right, especially with the ln in there. Am I on the right track? What can I now do?