Engineering Sketching output waveforms while considering slew rate

[JC2000]

Homework Statement

Sketch the output voltage when input voltage applied to non inverting amplifier with gain 10 for a square wave input signal with peak to peak voltage $2 V$, $50 %$ duty cycle and frequency $1$ kHz. Supply Voltage is +12 V and -12V, the op amp has slew rate 0.5 V/ microsecond and the op amp is nulled initially.

Relevant Equations

Time Period = 1 / Frequency

Duty Cycle = (Pulse Width *100)/ Time Period

1. Using the frequency equation I know the time period is 1 millisecond.

2. The duty cycle (50%) equation tells me that the pulse width and the amplitude is 1 V.

3. Thus the input waveform looks like this : (?)

4. As the slew rate is 0.5 volts per microsecond, the output voltage would take 4 microseconds to go from -1 V to + 1V (?)

5. Thus the output waveform for one pulse should look like :

(I converted milliseconds to microseconds)

Is this correct?

 

[cnh1995]

5. Thus the output waveform for one pulse should look like :

You have not considered the gain.

 

[JC2000]

You have not considered the gain.

Oof! Careless of me. Other than that bit is the rest fine?

 

[berkeman]

Oof! Careless of me. Other than that bit is the rest fine?

The horizontal axis is not to scale, even ignoring the voltage gain issue. The rise/fall times are on the order of a few us, while the period of the square wave input is on the order of a ms. Do you have any ideas for how to represent that on a plot? How would you observe this on a digital oscilloscope, for example?