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Skiier force down a slope

  1. Jun 22, 2013 #1
    1. A skier of mass 51.4 kg comes down a slope of constant angle 26◦ with the horizontal. What force normal to the slope is exerted by the skis (neglect friction)? The acceleration of gravity is 9.8 m/s^2.



    2. Relevant equations

    F=ma

    3. The attempt at a solution

    my intuitions tell me to do this:

    F=m*g*cos26

    am i wrong?
     
  2. jcsd
  3. Jun 22, 2013 #2
    i already did this!
     
  4. Jun 23, 2013 #3

    PeterO

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    Homework Helper

    A hint on how to think:

    The answer is either m*g*cos26 or m*g*sin26

    Suppose the slope was ≈ 0 degrees; one of m*g*cos0 or m*g*sin0 is zero.

    If the slope was ≈ 0 degrees, would the normal force be ≈ 0 ?

    That shows which one is NOT the answer.
     
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