Undergrad Calculate Skydiver Deceleration Force

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SUMMARY

The force exerted on a skydiver during deceleration from terminal velocity to a lower speed can be calculated using the values provided in the discussion. The skydiver decelerates from 120 mph (176 ft/sec) to 30 mph (44 ft/sec) over one second, resulting in a deceleration of 132 ft/sec², equivalent to approximately 4 g's. This calculation assumes contact deceleration, which equipment manufacturers aim to optimize. Additionally, the discussion highlights the importance of managing jerk to minimize the initial deceleration impact.

PREREQUISITES
  • Understanding of basic physics concepts such as force and acceleration
  • Familiarity with units of measurement, specifically feet per second (ft/sec)
  • Knowledge of gravitational acceleration (g's) and its implications in physics
  • Awareness of skydiving dynamics and equipment design considerations
NEXT STEPS
  • Research the physics of deceleration and forces in free fall
  • Explore the effects of jerk on human tolerance during rapid deceleration
  • Study equipment design principles for skydiving to enhance safety
  • Learn about terminal velocity calculations and their applications in various scenarios
USEFUL FOR

Aerospace engineers, skydiving instructors, physics students, and safety equipment designers will benefit from reading this discussion.

Vikinglord
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I'm wondering how to calculate the force exerted on a skydiver as they decelerate from their terminal velocity of approximately 120 mph to approximately 30 mph in the course of one second, as I have seen and felt while skydiving. Thank you all in advance.
 
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120 mph is 176 ft/sec and 30 mph is 44 ft/sec. So the deceleration is 132 ft/sec^2. This is about 4 g's.
 
Note that that assumes contact deceleration, which I would think equipment manufacturers try to achieve.
 
Instead of constant deceleration, there's some effort to also reduce the jerk, so that the initial deceleration is not as great as the maximum deceleration.
 

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