Slide Block Problem With Strings

AI Thread Summary
The discussion revolves around a system of three blocks connected by massless strings on a frictionless surface, with specific masses and a force applied to M3. Participants clarify that the entire system accelerates as one unit due to the external force acting on M3. To solve for the tension T2, one should first calculate the overall acceleration of the system and then analyze the forces acting on each block individually. The approach involves treating the blocks collectively and then isolating them to determine individual tensions. Understanding this method allows for accurate calculations of tensions in the system.
Hypnos_16
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Three blocks on a frictionless surface are connected by massless strings, with M1 = 1.30kg, M2 = 2.20kg, and M3 = 3.40kg. Due to the force F acting on M3, the system accelerates to the right. Given that T1 is 4.10Newtons, calculate T2.

M1 = 1.30 kg
M2 = 2.20 kg
M3 = 3.40 kg
and T1 = 4.10N

it looks like this

(M1)---T1---(M2)---(T2)---(M3)------> F

i don't know what to do here, i don't know if the whole thing moves as one, or if the force is just on M3 and all the other ones would have different forces working on them.
I'm very confused
 
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Hi Hypnos_16! :smile:
Hypnos_16 said:
Three blocks on a frictionless surface are connected by massless strings, with M1 = 1.30kg, M2 = 2.20kg, and M3 = 3.40kg. Due to the force F acting on M3, the system accelerates to the right. Given that T1 is 4.10Newtons, calculate T2.

(M1)---T1---(M2)---(T2)---(M3)------> F

i don't know what to do here, i don't know if the whole thing moves as one, or if the force is just on M3 and all the other ones would have different forces working on them.

It does both! :biggrin:

Yes, the whole thing moves as one …

first treat the whole thing as a single body with only one external force (F): that gives you the acceleration​

but you can also look at the forces just on M3 (or any other mass) …

then pick off the masses one at a time (I'd start from the left), using the acceleration you've already found, to find the individual tensions :smile:
 
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