# Sliding collar

1. Feb 16, 2016

### harmyder

1. The problem statement, all variables and given/known data
Initially collar is at rest with theta = 0. Find $$\dot\theta=f(\theta).$$ And find maximum theta reached.

2. Relevant equations
I don't know if i allowed to use angular momentum about top-right frame corner as it's accelerating.

But i definitely will need second Newton law:)

3. The attempt at a solution
I know that there mg, N forces. But i can't figure out another force due to acceleration of the frame.

2. Feb 16, 2016

### haruspex

Are you comfortable using non-inertial frames of reference?

3. Feb 16, 2016

### harmyder

I think i'm not, but i believe there is no need in it here. Important thing is that i need to calculate θ' based on θ not on t.

4. Feb 16, 2016

### haruspex

It does help here, but it is never essential.
What force/acceleration equations can you write? It doesn't matter if you think they are wrong or incomplete, just post what you get.

5. Feb 20, 2016

### harmyder

The collar undergoes three forces - $m\mathbf{g}, \mathbf{N}, \mathbf{F}_{ext}$. From which $|m\mathbf{g}|=|N|$, though i can't prove it.

With angle $\theta$ we have:
$|m\mathbf{g}|$ acting downward and $\big(|\mathbf{N}| + |\mathbf{F}_{ext}|\big)\cos\theta$ acting upward.

The maximum angle is reached with equilibrium.

And here i can't calculate the external force.

6. Feb 20, 2016

### haruspex

The external force acts on the frame, not on the collar.
Why do you think |mg|=|N|? Consider horizontal and vertical separately.

7. Feb 20, 2016

### harmyder

I can't come up with solution in $\hat{i}\times\hat{j}$ frame.

Maybe i need to consider tangential parts of $mg$ and anther force, i think this another force is $ma$? When they become equal, then no more change of angle.

8. Feb 20, 2016

### HallsofIvy

Staff Emeritus
The original post said "Initially collar is at rest with theta = 0" and according to the picture "theta= 0" is at the bottom! The collar won't move- $\theta'= 0$. If you intended to the initial point to be at the top, with "theta" measured from the top, then, at each $\theta$, the downward acceleration vector, <0, -g>, can be written as the sum of two vectors, one parallel to the normal vector circular bar and one parallel to the tangent vector. Since the collar can't move normal to the bar, only the tangent vector is relevant.

9. Feb 20, 2016

### harmyder

Have you noticed rightward horizontal acceleration of the frame?

10. Feb 20, 2016

### haruspex

That is the non-inertial frame method I mentioned. You treat the acceleration as a 'fictitious' force ma acting the other way.
So what answer do you get?

11. Feb 20, 2016

### HallsofIvy

Staff Emeritus
NO! I hadn't. Thanks.