Small mass attached to a string sliding between two circles

AI Thread Summary
A small mass M attached to a string slides between two circles on a frictionless table, with circle X having a radius twice that of circle Y. The discussion revolves around the work done by force F, kinetic energy comparisons, torque presence, and angular momentum and velocity relationships as M transitions from Y to X. Key calculations suggest that M's kinetic energy at X is one quarter that at Y, and angular momentum and velocity relationships are also explored. Participants emphasize the importance of understanding the formulas for work, kinetic energy, torque, and angular momentum. Clarification on these concepts is sought to resolve uncertainties in the homework problem.
sharkmanic
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Homework Statement



A small mass M attached to a string slides in a circle (Y) on a frictionless horizontal table, with the force F providing the necessary tension (see figure). The force is then decreased slowly and then maintained constant when M travels around in circle (X). The radius of circle (X) is twice the radius of circle (Y).

http://imgur.com/w970m

Possible answers (T,F,>,<,=)

As M moves from Y to X, the work done by F is ... 0.
M's kinetic energy at X is one quarter that at Y.
While going from Y to X, there is no torque on M
M's angular momentum at X is ... that at Y.
M's angular velocity at X is one quarter that at Y.

Homework Equations



I=mr^2
x=2y
etc..

The Attempt at a Solution



The main problem I run into, is that the HW system does not show you what you got right and what you got wrong. It's an all or nothing question. Anyway.

I've done some calculations and I think that the Wy = 4*Wx, and Iy = (1/4)Ix but I am not sure about the others, or if those are even correct. If someone could walk me through the reasoning behind these that would be great!
 
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sharkmanic said:

Homework Statement



A small mass M attached to a string slides in a circle (Y) on a frictionless horizontal table, with the force F providing the necessary tension (see figure). The force is then decreased slowly and then maintained constant when M travels around in circle (X). The radius of circle (X) is twice the radius of circle (Y).

Possible answers (T,F,>,<,=)
Haven't seen a question yet!
(1) As M moves from Y to X, the work done by F is ... 0.
(2) M's kinetic energy at X is one quarter that at Y.
(3) While going from Y to X, there is no torque on M
(4) M's angular momentum at X is ... that at Y.
(5) M's angular velocity at X is one quarter that at Y.

The main problem I run into, is that the HW system does not show you what you got right and what you got wrong. It's an all or nothing question. Anyway.

I've done some calculations and I think that the Wy = 4*Wx, and Iy = (1/4)Ix but I am not sure about the others, or if those are even correct. If someone could walk me through the reasoning behind these that would be great!
I suspect you've been over-thinking it.
Tackling them one at a time:
(1) W=Fd - which distance is important for F?
(2) How do you calculate kinetic energy?
(3) What would a torque do to the motion? Has this happened?
(4) You know the formula for angular momentum!
(5) You know the relationship between angular velocity and angular momentum!
 
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