Small Oscillations: Spring Constant & Frequency

AI Thread Summary
For small oscillations, the behavior resembles that of a spring, with the potential energy approximated by a parabola at equilibrium. The effective spring constant is derived from the second derivative of the potential energy function, leading to the frequency formula w = sqrt(k/m). Confusion arises when applying this to a pendulum, where the potential energy function U(t) = mgL(1-cos(t)) results in an effective spring constant of mgL, leading to a frequency that seems inconsistent with standard formulas. However, using the moment of inertia (I = ml^2) instead of mass clarifies the situation, aligning the results with expected outcomes. This illustrates the importance of the variable used in the calculations, confirming that the method holds when expressed in terms of horizontal displacement rather than angular displacement.
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For small oscillations, the oscillation behaves like a spring, because the potential energy function can be approximated by a parabola at the equilibrium point. Now, the effective spring constant in these situations is equal to the second derivative of the potential energy function, and so the frequency w = sqrt(k/m), where k is the second derivative of the potential energy function.

I'm confused by this. In particular, I don't understand when this actually works. For example, for a pendulum, the potential energy function is U(t) = mgL(1-cos(t)), where t is theta. In this case the effective spring constant is mgL, so w = sqrt(gL). Obviously this doesn't agree with the accepted formula (which is also for small angles only). So what's going on here?
 
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Hmm, it occurs to me now that if insead of m, i use the moment of inertia I = ml^2, i get the right formula. Is this a coincidence?
 
Yes, if you write it as a function of x, horizontal displacement, rather than theta, it comes out all right.
 
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