Smoothing with full wave rectification

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SUMMARY

Full wave rectification can produce a smooth voltage output by utilizing capacitors to reduce ripple. The optimal capacitor value is determined by the formula C = Vp / (2 * R * f * Vr), where Vp is the peak voltage, R is the load resistance, f is the frequency, and Vr is the desired ripple voltage. A larger capacitance results in a smaller ripple voltage, achieving a smoother DC output. Additionally, incorporating a voltage regulator can further stabilize the DC voltage and minimize ripple effects.

PREREQUISITES
  • Understanding of full wave rectification principles
  • Familiarity with capacitor selection and its impact on ripple voltage
  • Knowledge of voltage regulation techniques
  • Basic circuit analysis skills
NEXT STEPS
  • Research capacitor sizing for full wave rectifiers
  • Learn about voltage regulation methods, specifically linear and switching regulators
  • Explore circuit simulation tools like PSpice for testing rectification circuits
  • Study the effects of load resistance on ripple voltage in DC circuits
USEFUL FOR

Electrical engineers, hobbyists designing power supplies, and anyone involved in circuit design for applications like X-ray tubes will benefit from this discussion.

IntuitioN
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Hi all!

Is it possible to produce a smooth(or almost smooth) voltage through full wave rectification? I know for half-wave, you can use a capacitor, but this doesn't seem to work for full wave.

Cheers
 
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Sure it does. You may need to provide more information about what you are doing. IIRC, since a full wave rectifier has twice the ripple frequency of a half wave rectifier you will need to use a different valued cap for optimal performance.
 
You don't need to use a different cap, but you can get by with a smaller one. That is what engineering is all about though, getting by with as little as possible and still having things work correctly.
 
I think the diagram that I have attached achieves that, I did not test it properly in pspice though. The DC source represents your full wave rectification and the voltage across R1 should be smoothe enough
 

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hi guys thanks for ur replies!

What i am trying to do is to produce a smooth voltage to power an xray tube. I am trying to convert the AC currect into a DC current then smooth the voltage out so that the peak voltage is effectively the average voltage.

Exequor: What is L1? I'm not very good at this so can you please explain a bit how your circuit works?

Cheers
 
Last edited:
Go to my website www.abiscus.com and go to the rectified power supply link. On that page you'll find a PDF file explaining the theory behind rectification.

For a fullwave rectifier, the equation for the capacitor C is:

C = Vp / ( 2 * R * f * Vr )

where Vr is the voltage ripple, f is the frequency, R is the load resistance, and Vp is the peak voltage of the input.

As you can see, the larger the capacitance, the smaller the ripple voltage and the closer you will come to a smooth DC value.

You may also want to think about using a voltage regulator. This helps keep the DC voltage constant and further dampens the ripple.
 

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