Problems finding Volumetric Efficiency

[EngAngel]

1. The problem
DIESEL IC ENGINE
We were given a excel sheet, with RPM, Torque, Power, Bmep, Fuel mass flow rate, Airmass SFC, Engine Air inlet and Exhaust temp.

The engine capacity is 2.2litre 4 stroke.
Fuel specifications: 50 Cetane (0.05% Sulphur)
Coolant = Fresh water with 45% glycol mix.

I am having problems finding Volumetric Efficiency, the fuel calorific value and coolant specific heat.

Homework Equations

VE=(mRT/P)/(Vswept)
VE=(9411*HP*BSFC)/(displacement*RPM)

The Attempt at a Solution

I found a VE(volumetric efficiency) of 72.808% for the first speed of 1000RPM
with eq: VE=(9411*HP*BSFC)/(displacment*RPM)
=(9411*24.2*0.45)/(134*1000)

but seem to get the rest above 100% eg @2000RPM VE=133.856%
I have tried more than one equation, this seemed to get closer to the 70% VE it should be.

I also need to do a heat balance thus i require the calorific value of the diesel (it is not bio diesel fuel) as well as cp for the coolant.

Any assistance would be much appreciated.

 

[Adrmay]

SolutionTo calculate the Volumetric Efficiency, you need to use the following equation: VE = (mRT/P)/(Vswept), where m is the mass of air and fuel mixture, R is the specific gas constant, T is the temperature of the mixture, P is the pressure of the mixture, and Vswept is the swept volume of the engine.For the Fuel Calorific Value, you need to calculate the heat of combustion of the fuel. This can be done by measuring the energy released when a given amount of the fuel is burned. The heat of combustion is then divided by the mass of the fuel to get the calorific value.For the Coolant Specific Heat, you need to calculate the specific heat capacity of the coolant. This can be done by measuring the heat required for the temperature of the coolant to increase by 1 degree Celsius. The specific heat capacity is then calculated by dividing the heat by the temperature change.