I Solar chromosphere: inter-conversion of Ca I, Ca II, role of photons

AI Thread Summary
The discussion centers on the conversion of ionized calcium (Ca II) to non-ionized calcium (Ca I) in the solar chromosphere and the role of photons in this process. It is noted that atomic collisions at chromospheric temperatures can provide enough energy to eject an electron from Ca I, forming Ca II, without necessarily requiring a 393.37 nm photon for this transition. The question arises whether the absorption of a 393.37 nm photon is needed to elevate the electron to a higher orbital before it can be knocked out, or if collisions can directly free the electron from the lower orbital. Additionally, the presence of background 393.37 nm photons due to Black Body radiation is considered, suggesting that Ca II emissions might occur alongside a lower concentration of these photons. The conclusion drawn is that the generation of the Ca K emission line is not directly linked to the transition of the electron being ejected from the valence shell.
jordankonisky
Messages
41
Reaction score
3
TL;DR Summary
Does the mechanism of the formation of solar Ca I to Ca II require photons? What is the level of 393.37 nm photons in the solar chromosphere? Using Ca II filter to image solar Ca.
My question relates to the physics of the emission line of Ca II which originates in the solar chromosphere. My understanding is that ionized Ca which lacks a single electron in its valence orbital interacts with free electron in the chromosphere milieu to form Ca I (nonionized). The captured electron then moves from its capture orbital (4P 3/2) to the 4S 1/2 orbital and in the process generates a photon of lambda = 393.37 nm. This photon then travels to my telescope with a Ca II-K filter and then to my imaging camera.

My question is what is the mechanism by which that nonionized Ca I is converted to ionized Ca II. I have read that at the temperature of the chromosphere there is sufficient energy produced through atomic collisions to knock an electron out of the Ca I valence orbit to produce Ca II and a free electron. My question: does a photon of 393.37 nm play any role in the production of Ca II? Is it required that the leaving electron be kicked up to its capture orbital (4P 3/2) via absorption of a 393.37 nm photon before a collision can knock the electron out of Ca I to produce Ca II? Or can the collision free an electron from Ca I directly out of 4S ½ without the intervention of a 393.37 nm photon?

Finally, if there were no Ca in the chromosphere, wouldn’t there be some background of some 393.37 nm photons via the Black Body radiation profile? So, what I image are Ca II photons over a much lower concentration of free 393.37 nm photons. Hope I’m thinking about this right.
 
Astronomy news on Phys.org
jordankonisky said:
Summary:: Does the mechanism of the formation of solar Ca I to Ca II require photons? What is the level of 393.37 nm photons in the solar chromosphere? Using Ca II filter to image solar Ca.

My question relates to the physics of the emission line of Ca II which originates in the solar chromosphere. My understanding is that ionized Ca which lacks a single electron in its valence orbital interacts with free electron in the chromosphere milieu to form Ca I (nonionized). The captured electron then moves from its capture orbital (4P 3/2) to the 4S 1/2 orbital and in the process generates a photon of lambda = 393.37 nm. This photon then travels to my telescope with a Ca II-K filter and then to my imaging camera.

My question is what is the mechanism by which that nonionized Ca I is converted to ionized Ca II. I have read that at the temperature of the chromosphere there is sufficient energy produced through atomic collisions to knock an electron out of the Ca I valence orbit to produce Ca II and a free electron. My question: does a photon of 393.37 nm play any role in the production of Ca II? Is it required that the leaving electron be kicked up to its capture orbital (4P 3/2) via absorption of a 393.37 nm photon before a collision can knock the electron out of Ca I to produce Ca II? Or can the collision free an electron from Ca I directly out of 4S ½ without the intervention of a 393.37 nm photon?

Finally, if there were no Ca in the chromosphere, wouldn’t there be some background of some 393.37 nm photons via the Black Body radiation profile? So, what I image are Ca II photons over a much lower concentration of free 393.37 nm photons. Hope I’m thinking about this right.
 
I figured this out myself It is not the transition of the electron per se that is knocked out of the valence shell that generates the Ca K emission line.
 
This thread is dedicated to the beauty and awesomeness of our Universe. If you feel like it, please share video clips and photos (or nice animations) of space and objects in space in this thread. Your posts, clips and photos may by all means include scientific information; that does not make it less beautiful to me (n.b. the posts must of course comply with the PF guidelines, i.e. regarding science, only mainstream science is allowed, fringe/pseudoscience is not allowed). n.b. I start this...
Today at about 4:30 am I saw the conjunction of Venus and Jupiter, where they were about the width of the full moon, or one half degree apart. Did anyone else see it? Edit: The moon is 2,200 miles in diameter and at a distance of 240,000 miles. Thereby it subtends an angle in radians of 2,200/240,000=.01 (approximately). With pi radians being 180 degrees, one radian is 57.3 degrees, so that .01 radians is about .50 degrees (angle subtended by the moon). (.57 to be more exact, but with...
Back
Top