Designing a Solenoid Driver Circuit - Max Force of 2.75 lb

[Mike Phan]

Hi,

I am designing a solenoid driver ckt. The solenoid can hold a max force of 2.75lb. If I want my ckt drives the solenoid with max force, what current or power the ckt need to draw?

Thanks for any help.

Mike

 

[berkeman]

One way to approach this problem is to look up some typical datasheets for commercial solenoids. Google some solenoid datasheets, and see what voltage and current ratings seem to go with what pull / hold forces.

Then after that, you should be able to do your own calculations for number of turns and current to make a B field with a spreading that makes the pull force...

 

[ravenprp]

Hi Mike,

To calculate the current or power needed for your solenoid driver circuit to achieve a max force of 2.75 lb, you will need to know the specifications of your solenoid and the voltage supply available for your circuit.

First, determine the resistance of your solenoid by dividing the supply voltage by the maximum current rating of your solenoid. This will give you the maximum current that can be supplied to the solenoid.

Next, use Ohm's law (V=IR) to calculate the voltage needed to achieve a force of 2.75 lb. This will give you the minimum voltage required for your solenoid to reach its maximum force.

To determine the power needed for your circuit, multiply the calculated voltage by the maximum current rating of your solenoid. This will give you the power in watts that your circuit needs to draw to achieve a max force of 2.75 lb.

Remember to also take into account any losses in your circuit, such as resistance in the wires or components, and make sure your power supply can provide enough current to meet the demands of your solenoid driver.

I hope this helps. Good luck with your solenoid driver circuit design!