Solenoid flux-emf-current problem

  • Thread starter Thread starter crbnmnxd3
  • Start date Start date
  • Tags Tags
    Solenoid
AI Thread Summary
The discussion revolves around solving a problem involving a solenoid inductor with given emf, current change rate, and magnetic flux per turn. The key equations for magnetic flux and magnetic field strength are identified, but the user struggles with the lack of information about the solenoid's radius, which is necessary to calculate the surface area. The relationship between the two cases presented in the problem suggests that combining the equations will lead to a solution for the unknown number of loops in the solenoid. The user is encouraged to find the ratio of area to length using the provided information. Overall, the focus is on applying the relevant equations to derive the required value.
crbnmnxd3
Messages
2
Reaction score
0

Homework Statement


A solenoid inductor has an emf of 0.20 V when the current through it changes at the rate 10.0 A/s. A steady current of 0.10 A produces a flux of 5.0 microWb per turn.

The number of loops in the solenoid is the value which needs to be found.

Homework Equations





The Attempt at a Solution


I have been going through this problem for a good hour, and am simply stuck. Clearly there are two different cases which are presented for the same solenoid, which clearly means that each case needs to be plugged into an equation and these two equations must be related through an unknown variable. Please state any equations you may use in the solving of this problem, I have two pages of fruitless work in front of me.
 
Physics news on Phys.org
\phi=BA

B= \frac{\mu NI}{l}

N=No. of turns
l=length.

You'll need those 2.
 
The problem I keep running into with the first equation you listed is that I do not know what the radius of the solenoid is, and as a result I am unable to determine the surface area of the solenoid.
 
Combining the 2 equations you'll get

\phi = \frac{\mu NIA}{l}


Dividing both sides by N


\frac{\phi}{N}=\frac{\mu IA}{l}

Can you use the second line of the question to find a value for the ratio of \frac{A}{l}?


Then use the fact that

E=\frac{d}{dt}{\phi}

or simply

E=\frac{\phi}{t}
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top