Find the volume formed by rotating the area contained by y=sqrt(6x+4), the y-axis and the line y=2x about the y-axis. Set up, but do not evaluate the integral. First I graphed it, then did the "washer" method of finding the area of the circle formed, and found that the radius is (y/2-sqrt[(y^2-4)/6]. Is this right? I then found the height, which would be sqrt(y/2-sqrt[(y^2-4)/6], wouldn't it? Then the answer is: the integral from 0 to 4 of pi times the radius squared, times the height times dy. I don't have an answer key, but could someone help me with this?