Solution molarity change in electrolytic cell

AI Thread Summary
In the electrolysis cell containing 1L of 1M copper(II) sulfate, the passage of 0.4 moles of electrons results in the deposition of 0.2 moles of Cu2+ at the anode and the absorption of 0.2 moles at the cathode. This process leads to no net change in the concentration of copper ions in the solution. Therefore, the molarity of copper ions remains at 1.0 M. The conclusion drawn is that the correct answer is C, indicating no change in molarity. The reasoning behind this is confirmed as accurate.
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Homework Statement



The diagram below shows an electrolysis cell which contains 1L of an aqueous 1M copper(II)sulfate solution.

upload_2016-6-30_15-43-12.png


If 0.4 moles of electrons pass through the cell, the concentration of copper ions after passage of the charge will be

A) 0.4 M

B) 0.8 M

C) 1.0 M

D) 1.2M.

2. Homework Equations

The Attempt at a Solution



I chose C because if 0.4 moles of electrons pass through the cell, then that means 0.2 moles of Cu2+ will be deposited into the solution from the anode and that means 0.2 moles of Cu2+ will be absorbed by the cathode. This gives no net change in molarity in the solution. Is this correct?

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