Solve (-1/2)^x=1/4 with TI-Titanium Calculator

AI Thread Summary
The user encountered an issue with the "solve()" function on their TI-Titanium calculator when trying to solve the equation (-1/2)^x = 1/4, expecting the answer to be 2. Instead, they received a "false" response. It was suggested that the "solve()" function may restrict its algorithm to real numbers, leading to complications with the equation. To obtain the correct answer, using the "csolve()" function can provide complex solutions, including the desired value of 2, but requires additional steps to isolate the real solution. It is also recommended to solve such equations manually for better understanding and to use the calculator primarily for verification.
2Xist
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Dear PF,

Your last help to my tech support was very helpful and i thank you all for it :). however since i am new to my TI-Titanum, i unfortunalty have another stupid question. i was using the "slove(" function. and i inserted into the home screen (exactly what i typed in):

solve((-1/2)^x=1/4,X)

i mean... the answer should be 2 right?
somehow i got a "false" answer
i was just wondering if it is my calculators problem or if if everyones calcucators.
Please try on your own calculators and post results

thank you and please reply asap :)
 
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Perhaps you should try == rather = and see what you get.
 
Hi 2Xist,

2Xist said:
Dear PF,

Your last help to my tech support was very helpful and i thank you all for it :). however since i am new to my TI-Titanum, i unfortunalty have another stupid question. i was using the "slove(" function. and i inserted into the home screen (exactly what i typed in):

solve((-1/2)^x=1/4,X)

i mean... the answer should be 2 right?
somehow i got a "false" answer
i was just wondering if it is my calculators problem or if if everyones calcucators.
Please try on your own calculators and post results

thank you and please reply asap :)

I believe solve() restricts its algorithm to be over real numbers; while it is trying to solve your equation for x it runs into a complex expression.

If you use csolve() you will get a sequence of complex answers (as a complicated expression) one of which is the value 2; you can find the real answer you're looking for by forcing the imaginary part of the sequence to be zero. I don't think that's very practical if all you want is the real solution, but it does work.

You can eliminate the negative sign by hand (putting a contraint on x) and the use solve(). (But I hope you're solving all the problems by hand and only trying to check your work using solve().)
 
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