Solve 10 US gal of Jell-O Freezing in Locker Freezer at -10 °F

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The discussion revolves around calculating the cooling time for 10 US gallons of a Jell-O solution placed in a locker freezer at -10°F. The solution consists of 5 gallons of boiling water mixed with 5 gallons of a 99% water solution. To determine the cooling time to 35°F, the specific heat of the mixture and the freezer's cooling capacity need to be established. Newton's law of cooling is suggested as a method for estimation, requiring the calculation of specific heat and the freezer's output in BTU/min. Additionally, a middle school student seeks the specific heat of Jell-O for a science project, highlighting the need for accessible information on this topic.
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As I am actually performing this, it occurred to me I'm a bit rusty and cannot define the formula to calculate the following process. Anyone who can solve this and show a proof, your help would be appreciated. NO, I'm not a student looking for someone to do my work, I've been out of school for 7 years... which is why I'm rusty.

10 US gal of a solution is made using 5 gal of boiling water, added to 5 gal of a solution (which is 99% water).
These 10 gal are then placed in an empty locker freezer, which is approx 10 cubic ft, and has an ambient temp of -10 degrees(F).

My question is: how long should it take to cool the solution to 35 degrees(F)?
I have not been able to figure out cold output of the freezer, so answer would have to use a variable to define the strength of the freezer's output in the formula for "t".

Thanks in advance.
 
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Without going into a huge heat transfer analysis, I'd estimate it using Newton's law of cooling:

q = m C_p \Delta T

The only thing you'll have to do is to use a bit of chemistry to calculate the specific heat of the mixture. Once you know that, you need the capacity of the freezer in some units along the lines of btu/min to calculate the time necessary.
 
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Hello,

I am a student doing a science project where I need to know the specific heat of Jell-O. I googled "specific heat of Jell-O" and this thread came up. Sorry to be a bit random, but do you know the specific heat of Jell-O? It would help me immensely, as I have not had enough schooling yet to know how to calculate this.

Thank you,

A middle school student
 
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