Solve 2D Elastic Collision Homework Statement

AI Thread Summary
The discussion revolves around solving a 2D elastic collision problem involving two objects with specified masses and velocities. The key equations derived include momentum conservation and kinetic energy conservation, leading to relationships for the initial speed v0 and angles θ1 and θ2 after the collision. It is established that θ1 equals θ2, simplifying the calculations. The participants clarify that without numeric values for speeds, v0 can only be expressed in terms of v1. Ultimately, the consensus emphasizes the need for dimensional analysis to derive numerical solutions.
Taylor T
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Homework Statement


Problem: An object of mass m1 elastically collides with an object of mass m2 =(3/2) m1 that is initially at rest. The less massive object has speed v1 and travels at an angle of θ1with its original direction (x-axis) after collision; the more massive object has a speed of v2 = (2/3) v1 and travels at an angle of θ2 after collision. What are the initial speed v0 of the less massive object and the two scattering angles, θ1 and θ2?

known values ( symbolically at least)
m1
m2 = 1.5 m1
v1f
v2f = 2/3 v1f

Finding:
v0
θ1
θ2

Homework Equations


Momentum Equations:[/B]
Pi=Pf
KEi=KEf
Before:
Px: m1*v0
Py: 0
E: 1/2 m1*v0^2
After:
Px: m1*v1f*cos(θ1)+3/2 m1 * 2/3 v1f cos(θ2)
Py: m1*v1f*sin(θ1)-3/2 m1 * 2/3 v1f sin(θ2)
KE: 1/2 m1* v1f^2+1/2 3/2 m1 (2/3v1f)^2

Combined:
(1)KE: v0^2=5/3 v1f^2
(2)Px: m1v0 = m1*v1f cos(θ1) + m1*v1f cos(θ2)
(3)Py: m1*v1f sin(θ1) = m1*v1f sin(θ2)

The Attempt at a Solution


Equation (3)simplifies to sin(θ1)=sin(θ2)
(4) θ1=θ2
plugging (3) into (2)
(5) v0 = 2*v1f cos(θ1)
plugging 5 into 1
(2 v1f cos(θ1) ) ^2 = 5/3 v1f^2
solving for θ1 you get θ1=arccos( sqrt(15) / 6 ) which means θ2=arccos( sqrt(15)/6) as wellFrom here I am stuck trying to solve for v0. I am also unsure if my value for θ is correct.Thanks for the help.
 
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As the collision is elastic
Did you use the fact
That the total kinetic energy before the collision equals the total kinetic energy after the collision?

Use this

UchihaClan13
 
My bad. I forgot to label this fact carefully in the givens the Ei=Ef was non specific energy but it was intended to be kinetic energy. But yes I did take this into account
 
I agree with your solution for the angle (though I would have expressed it as arccos(√(5/12))).
Since you are given no numeric values for speeds, it is only possible to find v0 in terms of v1. Does that help?
 
That does definitely help knowing I got the angles correct. Is it still not possible to find the original velocities even though we know the relationships between the masses and their final velocities?
 
Taylor T said:
That does definitely help knowing I got the angles correct. Is it still not possible to find the original velocities even though we know the relationships between the masses and their final velocities?
Are you familiar with dimensional analysis? None of the numerical data you are given has an associated dimension, so it is not possible to come up with a numerical answer for a dimensioned quantity. Even knowing masses would not help. You would need to know at least one quantity involving distance and at least one involving time.
Just go ahead and find v0 in terms of v1.
 
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