Solve a Short Parabola Question with 2π/3 Period | Example Problem

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The discussion revolves around a problem involving a sine function with a period of 2π/3, but participants question its relevance to a parabola. The function is described as a constant value rather than a periodic function, leading to confusion about its characteristics such as amplitude and phase shift. There is a suggestion that the original question may contain an error, as it appears to ask for graphing a non-periodic straight line. One participant proposes a revised function that would better fit the context of the problem. The conversation highlights the need for clarity in mathematical problems involving trigonometric functions.
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2pi/3 the period right?
 
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3sin(2\pi /3)-4=-3.89...

It's not even a function (or a pretty boring one), it's a number And why do you associate a sine with a parabola?
 
I accidently made the assumption is was a parabola because the question asks for
amplitude, period, phase shift, domain, range, and vertical shift (but I know you can do this for a sine graph to)

Do you know how to graph it on a graphing calculator? I do not recall how to solve this type of problem =(
 
Well as I said it's a pretty boring function, it's a number. It's just a straight horizontal (if you plot y on the vertical axis) line throught the point y=3sin(2\pi /3)-4=-3.89.... I'm not sure it's meaningful to assign a period to it as it's not periodic.
 
there must be a mistake in the question, I am sure the book does not want us to graph a straight line over one full cycle?

I think it should be 3sin(x (not 0) - 2pi/3) -4
That would make much more sense

Thanks for your help will
 
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