- #1
Diganta28
- 3
- 0
1. Homework Statement :
A rod of length l is vertically standing on a friction less surface.
It is slightly disturbed from this position. Let w(omega) and alpha be the angular speed and angular acceleration of the rod, when it turns through an angle theta, then find the value of acceleration of centre of mass of the rod.
2. Homework Equations :
acom = ( Fnet/mnet)
tau = i * alpha
tau= force*perpendicular distance from axis of rotation
3. The Attempt at a Solution :
Tried like this (but no luck):
(mg-N)=ma , where a is the required answer.N * (l/2) sin theta = (1/12 m (l)^2) * alpha
Solved to get : a = g-(l * alpha/(6 sin theta)).
But answer given :
l *(alpha/2)* sin theta + (w^2*l/2) cos theta
A rod of length l is vertically standing on a friction less surface.
It is slightly disturbed from this position. Let w(omega) and alpha be the angular speed and angular acceleration of the rod, when it turns through an angle theta, then find the value of acceleration of centre of mass of the rod.
2. Homework Equations :
acom = ( Fnet/mnet)
tau = i * alpha
tau= force*perpendicular distance from axis of rotation
3. The Attempt at a Solution :
Tried like this (but no luck):
(mg-N)=ma , where a is the required answer.N * (l/2) sin theta = (1/12 m (l)^2) * alpha
Solved to get : a = g-(l * alpha/(6 sin theta)).
But answer given :
l *(alpha/2)* sin theta + (w^2*l/2) cos theta
