Given H2SO4 + 2LiOH --> Li2SO4 + 2H2O, how many mL of a 0.700-M solution of KOH are needed to react with 235 mL of a 0.350-M H2SO4 solution?
The Attempt at a Solution
Really, I have none. My problem is that I don't understand what the question is asking. I could probably figure this out but for some reason my brain can't reason out what I'm supposed to be aiming for here? Is it wanting to know how many mL of KOH are needed to neutralize the H2SO4? If so, I don't need the given equation do I? Maybe just a hint would send me in the right direction... Then again maybe I am just totally lost.
Thanks in advance for any and all help...