- #1

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**The problem**

Solve ## e^x-e^{-x} = 6 ## .

**The attempt**

$$ e^x-e^{-x} = 6 \\ e^x(1-e^{-1}) = 6 \\ e^x = \frac{6}{(1-e^{-1})} \\ x = \ln \left( \frac{6}{1-e^{-1}} \right) \\ $$

The answer in the book is ## \ln(3 + \sqrt{10})##

**Could someone help me?**