Solve Balloon Problem Homework: Time & Speed Impact

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Homework Help Overview

The problem involves a hot-air balloon ascending at a rate of 12 m/s, with a package dropped from a height of 80 m. Participants are tasked with determining the time it takes for the package to reach the ground and the speed at which it impacts the ground.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to solve for time and final speed, with some suggesting the need to rearrange the equations to isolate time. There is a focus on the correct formulation of the equations and the implications of the initial conditions.

Discussion Status

Multiple interpretations of the kinematic equations are being explored, with participants attempting to clarify the correct form of the equation to use. Some guidance has been provided regarding the quadratic formula, but there is no consensus on how to isolate time effectively.

Contextual Notes

Participants are working under the constraints of the problem's initial conditions and the requirement to use specific kinematic equations. There is an ongoing discussion about the values of acceleration and initial height, which may affect the setup of the equations.

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Homework Statement


Question: A hot-air balloon is ascending at the rate of 12m/s and is 80m above the ground when a package is dropped over the side.
a.)How long does the package take to reach the ground? b.)With what speed does it hit the ground?

Homework Equations


I know -- acceleration = -9.8 Initial velocity = 12 m/s and initial height = 80 m.

I know I have to use this formula
Xf = Vo + 1/2 (g) (T)2

Vo = 12 m/s
Xf = 80 m
g = -9.8 m/s2

I set Xf to 0.How would I find Time?

Thanks
 
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CrossFit415 said:
I know I have to use this formula
Xf = Vo + 1/2 (g) (T)2
I think you mean:
Xf = Xo + Vo(T) - 1/2 (g) (T)2
where g = 9.8 m/s2
How would I find Time?
Time is the only unknown in the above quadratic equation, so solve for T.
 
How would I go on about doing that? I can't seem to get T by itself in this equation.
 
Doc Al said:
I think you mean:
Xf = Xo + Vo(T) - 1/2 (g) (T)2
where g = 9.8 m/s2

Time is the only unknown in the above quadratic equation, so solve for T.

That user is correct by the way because this is the form you should get. Well, since the object starts 80 m above the ground, x_0 = 80 obviously.

Here is the equation you get:

x_f = 80 + 12t - 4.9t²

CrossFit415 said:
How would I go on about doing that? I can't seem to get T by itself in this equation.

It's not impossible to find t. To find t, use the quadratic equation as that user indicates. That is the way to find t. Remember that:

at² + bt + c = 0 OR c + bt + at² = 0

t = (-b ± √(b² - 4ac))/(2a)

OR

t = (-b + √(b² - 4ac))/(2a) or t = (-b - √(b² - 4ac))/(2a)

By letting the corresponding values be the a, b, c variables and then, solving for t, you should get the answer (it must be positive!).
 

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