Solve Basic Limit Question Homework Equation

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Homework Statement


http://u1.imgupload.co.uk/1257984000/d192_image.gif

Homework Equations


above

The Attempt at a Solution



1st part should be okay for me and my ans is e^(2c)

for the 2nd part, i have tried to use f'(x)=lim h-->infinity f(x+h)-f(x) / h and that just prove f'(x)=e but i found it maybe useless for finding c. so any hints can give me??

or may i treat right side of the inquality as lim x--> infinity f(x) - lim x--> infinity f(x-1) ?

thx:blushing:
 
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Look at the right hand side of your second part. Notice that it's

limit as x gets large of: ( f(x) - f(x-1) ) / ( x - (x-1))

If the actual derivatives of f are approaching a slope of e as x gets large, then what do you suppose is happening to slopes of secants measured way out there where x is very large?
 
LumenPlacidum said:
Look at the right hand side of your second part. Notice that it's

limit as x gets large of: ( f(x) - f(x-1) ) / ( x - (x-1))

If the actual derivatives of f are approaching a slope of e as x gets large, then what do you suppose is happening to slopes of secants measured way out there where x is very large?
soory i can't get what you mean. may be it is too theoretic for me..
 
Well, what is the form for the slope of a secant line to the graph of a function? How does that relate to the slope of the tangent line at some point?
 
delete

thx
 
Last edited:
Well done!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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