Solve Complex Integral: \oint \frac{f(z)}{z^{2}+1}dz

strangequark
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Homework Statement


Let \gamma_{r} be the circle centered at 2i with a radius r. Compute:

\oint \frac{f(z)}{z^{2}+1}dz


Homework Equations



2 \pi i f(w)=\oint \frac{f(z)}{z-w}dz

Cauchy's integral formula... maybe?

The Attempt at a Solution



I can see how to find solutions for two separate cases:

0<r<1
0<r<3
r>3

I have no idea how to find a general formula for this... nor am I sure what to do when \gamma passes thru a singularity...

any help on how to get started would be MUCH appreciated... thanks in advance
 
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If the curve passes through the singularity then it's really only defined in the principle value sense. I wouldn't worry about that case. But you are doing it right. You have to split the answer into cases, not write on big formula.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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