Solve Composite Function: g(f(x)) = 225?

AI Thread Summary
To solve for g(f(x)) where f(x) = x^3 + 3x^2 + 4x + 5 and g(x) = 5, it is important to recognize that g(x) is a constant function. Therefore, regardless of the input from f(x), g(f(x)) will always equal 5. The confusion arises from attempting to evaluate g(f(x)) as if it were a variable function, but since g(x) does not change, the result remains constant. Thus, g(f(x)) = 5, not 225. The key takeaway is that g(f(x)) simplifies directly to 5 due to the nature of g(x).
Loppyfoot
Messages
192
Reaction score
0

Homework Statement


If f(x) = x3+3x2+4x+5 and g(x)=5, then g(f(x)) = ?


Homework Equations





The Attempt at a Solution


I don't know if I am correct.
g(f(x)) =
g(x3+3x2+4x+5)= 225?

I plugged 5 into the equation. Am I right?
 
Physics news on Phys.org
Loppyfoot said:

Homework Statement


If f(x) = x3+3x2+4x+5 and g(x)=5, then g(f(x)) = ?


Homework Equations





The Attempt at a Solution


I don't know if I am correct.
g(f(x)) =
g(x3+3x2+4x+5)= 225?

I plugged 5 into the equation. Am I right?

If you plugged 5 into f(x), then you calculated f(5) = f(g(x)), since g(x) = 5. You want to find g(f(x)), which means plug f(x) into g(x).

If you're having trouble, maybe ask yourself, what's g(1), g(10), g(1000)? Once you see a pattern, then g(f(x)) shouldn't be much harder.
 
How do I plug a function into an integer? Would g(f(x)) just be 5?
 
g(x) isn't an integer. It's called a constant function. And yep, g(f(x))=5.
 
Back
Top