Solve Conical Pendulum: Find Speed, Period, Horiz. Comp., Rad. Accel.

AI Thread Summary
The discussion focuses on solving a conical pendulum problem involving a mass m suspended from a string of length L, revolving at an angle of 28°. Participants calculate the speed of the object as approximately 2.098 m/s and the period of revolution as 2.53 seconds. They explore the horizontal and vertical components of tension in the string and the radial acceleration, emphasizing the need to apply circular motion equations. Clarifications are made regarding the correct formulas for force and acceleration, and the importance of understanding the geometry of the pendulum to determine the radius r. The conversation highlights the necessity of accurate calculations and trigonometric relationships in solving the problem.
coolskool
Messages
1
Reaction score
0
The Conical Pendulum


A small object of mass m is suspended from a string of length L = 1.8 m. The object revolves in a horizontal circle of radius r with constant speed v and angle = 28°

Find the speed of the object.
i found s=v=2.098.

Find the period of revolution, defined as the time interval required to complete one revolution.
i found it to be ... t=2.53

NOW...

For the conical pendulum described above, determine the following if m = 14.0 kg.
(a) the horizontal and vertical components exerted by the string on the object
(b) the radial acceleration of the object.

for H my equation is
T=ma/sin theta

and to find a=s/t
i take what i found in the previous problem right?
so s=v=2.098
and t=2.53?

and for Fv my equation is T=mg/costheta?

and then for part b...mv^2/r...
but what is r?

OKAY i found everything BUT the HORIZONTAL COMPONENT!
HELP
 
Last edited:
Physics news on Phys.org
For the first part I get a slightly different answer for the speed and period. your answers are round about the same as mine so perhaps just using different constants.

For parts a and b, you will have to go back to the circular motion equations and find the horizontal force being exerted on the bob.

part b the equation you have used is for force but you want acceleration. Remember F=ma. Also you should know what r is from the first part of the question. Its simply a matter of trigonometry (i.e. the pendulum string forms a right angled triangle with the vertical and horizontal and you know the hypotenuse and one of the angles).
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top