- #36
Zetison
- 35
- 0
Yes, and this is what I get. I guess that's the far as I am going to get:
[tex]cos(\frac{1}{3}arccos(x)) = \frac{(x + \sqrt{x^2-1})^{1/3}}{2} + \frac 1 {2(x+\sqrt{x^2-1})^{1/3}} [/tex]
But again, my x is defined as
[tex]x = \frac{473419}{6121\sqrt{6121}} [/tex]
approximate [tex]x = 0.9885806704[/tex].
So my final goal here is to get exact values for
[tex]z = \frac{79}{60} + \frac{1}{30} \sqrt{6121} cos(\frac{1}{3}arccos(x)) = \frac{79}{60} + \frac{1}{30} \sqrt{6121} \frac{(x + \sqrt{x^2-1})^{1/3}}{2} + \frac 1 {2(x+\sqrt{x^2-1})^{1/3}}[/tex]
But that is very difficult to express when
[tex]x = \frac{473419}{6121\sqrt{6121}} [/tex].
Is it possible?
[tex]cos(\frac{1}{3}arccos(x)) = \frac{(x + \sqrt{x^2-1})^{1/3}}{2} + \frac 1 {2(x+\sqrt{x^2-1})^{1/3}} [/tex]
But again, my x is defined as
[tex]x = \frac{473419}{6121\sqrt{6121}} [/tex]
approximate [tex]x = 0.9885806704[/tex].
So my final goal here is to get exact values for
[tex]z = \frac{79}{60} + \frac{1}{30} \sqrt{6121} cos(\frac{1}{3}arccos(x)) = \frac{79}{60} + \frac{1}{30} \sqrt{6121} \frac{(x + \sqrt{x^2-1})^{1/3}}{2} + \frac 1 {2(x+\sqrt{x^2-1})^{1/3}}[/tex]
But that is very difficult to express when
[tex]x = \frac{473419}{6121\sqrt{6121}} [/tex].
Is it possible?
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