Solve Cyclotron Motion Homework

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An electron in a cathode-ray tube is accelerated through a 10 kV potential difference before entering a 2.4-cm-wide magnetic field. The solution involves using circular motion principles and geometry to determine the radius of the electron's path, calculated to be 10.669 cm. The relationship between mass, velocity, radius, charge, and magnetic field is applied, leading to an initial calculation of B as 4.1 * 10^-7 T. However, the angle theta, which is crucial for the calculations, was not initially provided and is determined to be 15°. Clarification on the angle and radius is essential for accurate results.
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Homework Statement


An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 2.4-cm-wide region of uniform magnetic field in the figure.
33.P59.jpg


Homework Equations


- Am I taking the entirely wrong approach in the solution?

The Attempt at a Solution


Since this is circular motion, we can draw a circle which intersects the square in the picture at where the electron exits the cathode ray tubes and the place it exits the square. Geometry then gives the angle between the tangent to the latter point and the hypotenuse, and we find that the radius is 10.669 cm. We could then use mv^2/R = qvB, and we know that 1/2mv^2 = q*10000 from the cathode ray tube. Solving for B gives B = 4.1 * 10^-7 T, which is incorrect.
 

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What is the angle theta?
It's not given in your question, how did you calculate the radius?
 
I didn't realize it wasn't given in the figure. Theta is 15°.
 
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