Solve d2y/dx3: Step-by-Step Guide

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Homework Help Overview

The discussion revolves around understanding the notation for derivatives, specifically the expression d2y/dx3, which appears to be a point of confusion for the original poster. The subject area is calculus, focusing on derivatives and their notation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the correct interpretation of the notation, with some suggesting it may be a typo and others clarifying the meaning of the second and third derivatives.

Discussion Status

The discussion is progressing with participants providing clarifications regarding the notation. The original poster acknowledges a mistake in their initial query and expresses a desire to understand the concept better.

Contextual Notes

The original poster mentions self-teaching, indicating a lack of formal guidance, which may influence their understanding of the topic.

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Homework Statement


[/B]
I've tried to search this up but to no avail. How am I suppose to solve this:

d2y/dx3

Homework Equations


N/A

The Attempt at a Solution



Here's what I think I need to do:

1: Square and cube y and x respectively.
2: Find the second and third derivative of y and x respectively.

Thank you.
 
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This looks like a typo, I think you need to ask your teacher what they want here or of course you could compute the ##d^2y/dx^2## and the ##d^3y/dx^3##

The superscripts aren't powers and these aren't fractions of differentials.

The notation means:
- 2nd derivative of y with respect to x for ##d^2y/dx^2## and
- 3rd derivative of y with respect to x for ##d^3y/dx^3##

Check to see if your book has an errata sheet online which would indicate whether its a typo that is if this came from your book otherwise check with your teacher.
 
Last edited:
Human error on my behalf. I mistype it. But yeah, thank you. I'm self-teaching (as scary enough as it is, ha ha) so no teacher besides myself

So basically it means to take the second (or nth) derivative? Thank you. .
 

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