Solve Diff. Equation System: Find Mistake

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Homework Help Overview

The discussion revolves around a system of differential equations involving two variables, x and y, with the objective of finding a solution. The original poster presents their attempts at solving the system and expresses confusion regarding the results obtained from the eigenvalues and eigenvectors.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find eigenvalues and eigenvectors for the system but questions the validity of their solution when both eigenvectors yield zero. Some participants suggest solving the eigenvector equations to clarify the situation.

Discussion Status

Participants are actively engaging with the original poster's reasoning and providing guidance on how to proceed with the eigenvector equations. There is an exploration of different forms of solutions, but no consensus has been reached regarding the correctness of the proposed solution forms.

Contextual Notes

There are indications of confusion regarding the eigenvector calculations and the implications of obtaining zero solutions. The discussion reflects a need for clarity on the eigenvector relationships and their impact on the overall solution.

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Homework Statement


System1:
dx/dt=x+y
dy/dt=8x-y


Homework Equations





The Attempt at a Solution


detreminant=(1-λ)(-1-λ)=(λ-3)(λ+3);λ[itex]_{1}[/itex]=-3 and λ[itex]_{2}[/itex]=3

So system 2:
(1-λ)[itex]\alpha[/itex]+[itex]\beta[/itex]=0
8[itex]\alpha[/itex]+(-1-λ)[itex]\beta[/itex]=0

When i put λ[itex]_{1}[/itex]=-3 in system 2 -> [itex]\alpha[/itex] and [itex]\beta[/itex]=0.
the same goes for λ[itex]_{2}[/itex]

That menas that solution in form of y=C_1*[itex]\beta[/itex]_1*exp(λ[itex]_{1}[/itex]*t)+C_2*[itex]\beta[/itex]_2*exp(λ[itex]_{2}[/itex]*t) is equal to 0. Thats wrong.

Where is my mistake?
 
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hi prehisto! :smile:

so far so good! …
prehisto said:
(1-λ)[itex]\alpha[/itex]+[itex]\beta[/itex]=0
8[itex]\alpha[/itex]+(-1-λ)[itex]\beta[/itex]=0

now solve either line to get β = 2α, so your eigenvector is any multiple of x + 2y :wink:
 
ok,that means that i can chose α1=1 β1=2 and
α2=1 β2=-4

y=C11*exp(λ1*t)+C22*exp(λ2*t)
x=C11*exp(λ1*t)+C22*exp(λ2*t)
Is this form of solution correct or I have to use something else?
 
i think it would be better if you checked by starting with the eigenvector equations

x + 2y = Ae3t
x - 4y = Ae-3t
 

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