Solve Elastic Collision | 2kg Object Moving at 3m/s Hits Stationary 4kg Object

AI Thread Summary
In an elastic collision involving a 2kg object moving at 3m/s striking a stationary 4kg object, the conservation of momentum and kinetic energy principles apply. The initial momentum of the system is calculated from the moving object, while the final momentum includes both objects post-collision. Given that the 4kg object moves at 0.5m/s after the collision, the final velocity of the 2kg object can be determined using these conservation laws. The relevant equations involve setting the total momentum before and after the collision equal, as well as ensuring that kinetic energy is conserved. Solving these equations will yield the final speed of the original 2kg object.
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Homework Statement



An object of 2kg moving at 3m/s hits a 4 kg stationary object, causing the stationary object to begin moving at 0.5m/s. How fast is the original object now travelling?

It is an elastic collision.

Homework Equations



Not really sure, 1/2mv^2 I presume.

The Attempt at a Solution



None so far, I'm stuck on it and am not sure how to approach it.
 
Physics news on Phys.org
What principle can be used in a collision?
 
Namely, what quantity involves mass and velocity, so we can use all your given data? What can we say about its value before and after the collision?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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