Solve Equivalent Resistance: Points A and B

AI Thread Summary
To find the equivalent resistance between points A and B, the resistors R3, R4, and R5 are first combined in series to form a new resistance, R'. The next step involves calculating the equivalent resistance of R1, R2, and the series combination (R' + R6) in parallel. The initial calculation of 0.53 ohms was incorrect, as the correct answer is 0.838 ohms, as stated in the textbook. The discussion emphasizes the importance of applying series and parallel rules for combining resistors effectively. Understanding the voltage in the loop is not necessary for solving this particular problem.
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Homework Statement



https://www.physicsforums.com/attachment.php?attachmentid=11955&stc=1&d=1197437955

Find the equivalent resistance between points A and B shown in the link above

Homework Equations



for parallel, equivalent resistance is =1/R1 +1/R2 +1/R3...
equivavalent resistance for series is = R1 + R2 + R3

The Attempt at a Solution



i believe they are all parallel or R3, R4, R5, and R6 are series becouse they depend on each other
 

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1/R= 1/1.5 + 1/2.5 + 1/4.3 +1/3.3 + 1/8.1 +1/6.3 =1.88
r=.53 ohm. this is not correct. the back of my book says .838 and can someone tell me how they got that answer
 
First find the parallel resistance of R3, R4 and R5, call it maybe R'. Now you see that R1, R2 and the series combination (R'+R6) are in parallel. That will give you the answer.
 
when can you say that the voltage in the loop will be zero? not in this case?
 
The voltage around any loop is zero, but that is not needed here. This problem can be solved using series and parallel rules for combining resistors.
 
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