Solve f''(t) for Vector-Valued Function f(t)

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SUMMARY

The discussion focuses on finding the second derivative, f''(t), of the vector-valued function f(t) = (e^(-t), cos(t)). The user initially struggles with the differentiation process, particularly distinguishing between the first and second derivatives. The correct approach involves taking the derivative of each component separately: f'(t) = (-e^(-t), -sin(t)), leading to f''(t) = (e^(-t), -cos(t)). This method clarifies the relationship between f(t), f'(t), and f''(t).

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Question:

If f is a vector-valued function defined by f(t)=(e^(-t), cos(t)), find f''(t).
I'm not even quite sure how to start.

Any help would be loved! Thank you!
 
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Ok, let me clarify. I attempted to take the derivative of each separate part (thus, e^-t became -e^(-t) and so on), but I don't know what to do with it.
 
What is the difference between ...

[tex]f'(t)[/tex] vs [tex]f''(t)[/tex] ?

Also, [tex]x=e^{-t}[/tex] and [tex]y=\cos t[/tex]

[tex]v(t)=<x=f(t),y=f(t),z=f(t)>[/tex]

You can take the derivative of each separately.
 

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