Solve for Height of Cliff After Diver Jumps Off at 2.2m/s

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AI Thread Summary
To determine the height of the cliff, the diver's vertical motion is analyzed using the equation Y = Yo + Vyo*t - 0.5gt^2. The diver's initial vertical velocity (Vyo) is zero since they dive horizontally. After substituting values into the equation, the calculated height (y) was found to be 25 meters, but this result was marked incorrect by the online homework system. The correct approach involves recognizing that the diver's horizontal speed does not affect the vertical fall, which is solely influenced by gravity over the 2.5 seconds. The correct height calculation must consider only the vertical motion, leading to a reevaluation of the inputs used in the equation.
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Homework Statement


A diver running 2.2 m/s dives out horizontally from the edge of a vertical cliff and 2.5 s later reaches the water below. How high was the cliff?


Homework Equations


Y=Yo+Vyo*t-.5gt^2

I have Y as being 0 (the point when they hit the water) and velocity of y at time zero being 2.2 m/s.


The Attempt at a Solution


I used the equation above and substituted and got 0=y+(2.2)(2.5)-.5(9.8)(2.5^2) and got 25 for y, but my online homework says it's wrong. I've double checked and can't figure out where I went wrong.
 
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The diver has an initial speed of 2.2m/s in the horizontal direction. What is the diver's initial speed in the vertical direction?
 
zero, because they are not moving either up or down yet, thank you very much!
 

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