Solve for Launch Velocity Components in a Football Field Goal Attempt

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To solve for the launch velocity components of a football field goal attempt, the ball experiences an acceleration of 390 m/s² for 0.050 seconds. Using the formula a = (v - v₀) / t, the final velocity can be calculated as v = a * t, resulting in a velocity of 19.5 m/s. The launch angle is given as 54°, allowing for the calculation of horizontal (vx) and vertical (vy) components using trigonometric functions. The horizontal component can be found with vx = v * cos(54°), and the vertical component with vy = v * sin(54°). This approach provides a clear method to determine the necessary launch velocity components for the field goal attempt.
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In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.050 s during which time it experiences an acceleration of 390 m/s2. The ball is launched at an angle of 54° above the ground. Determine the horizontal and vertical components of the launch velocity.

vx = ? m/s
vy = ? m/s
 
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I think this should be in the homework section.
 
a = \frac{v - v_o}{t}
390m/s^2 = \frac{v - 0m/s}{0.050s}

I think you know how to do the rest. If you dont, ask away.
 
Can u show me how to do the rest of the problem so I can make sure that I'm doing the problem the correct way.
 
Why don't you show us what you're doing then I'm sure someone will be happy to check your work.
 
shawonna23 said:
Can u show me how to do the rest of the problem so I can make sure that I'm doing the problem the correct way.

Personally, I wouldn't trust an answer given by anyone stupid enough to fall for that!
 
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