Solve Forces & Inclines Homework: Find Coefficient of Friction

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SUMMARY

The problem involves calculating the coefficient of kinetic friction (μ) for a 3kg block being pulled up a 37-degree incline with a tension of 45N at constant speed. The correct approach utilizes the equation T - mgsin(θ) - μ(NF) = 0, where NF is the normal force calculated as NF = mgcos(θ). The solution yields μ = 0.4, confirming the initial calculation was accurate. The discussion clarifies that the tension does not require a sine component since it is parallel to the incline.

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Homework Statement



A 3kg block is pulled by a rope up a 37 degree incline at constant speed. If the tension in the rope is 45N and the rope is parallel to the incline, calculate the coefficient of kinetic friction between the block and the incline.

Homework Equations



a = acceleration (0 m/s2)
Ө = theta (37 degrees)
g = 9.8 m/s2
m = mass
T = Tension
μ = coefficient of friction
NF = Normal Force
friction = μNF
NF = mgcosӨ


The Attempt at a Solution



My attempt was setting up the equation: TsinӨ - mgsinӨ - friction = ma
OR 45sin(37) - (3)(9.8)sin(37) - μ(3)(9.8)cos(37) = 0
OR 27.1 - 17.7 = μ23.5
OR 9.4 = μ23.5
Finally, μ = .4

Just wondering if it's correct. =)
 
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TsinӨ - mgsinӨ - friction = ma

You don't need a sinӨ multiplying the tension, the force of the tension is given parallel to the plane so you wouldn't need to factor an angle in, make sense?
 
Cool, because I did try it that way and i got μ = 1.16 and I thought I was wrong so I concluded with adding a random sinӨ lol.
 

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