Solve Free Electron Laser Homework Equations

  • Thread starter Thread starter Raz91
  • Start date Start date
  • Tags Tags
    Electron Laser
Raz91
Messages
20
Reaction score
0

Homework Statement


i1k9vm.jpg



Homework Equations


2. (b)

I didn't understand how can I find the app. wavelength


The Attempt at a Solution



I tried : the electron move over λu with velocity β so the wavelength is λ≈λu
but its not the right answer.

my lecturer told me I should consider also the dopler

I only know that the answer is :
λ≈λu /(2*γ2)

γ= gamma
THANK YOU!
 

Attachments

  • ??? ??.jpg
    ??? ??.jpg
    42.9 KB · Views: 430
Physics news on Phys.org
Raz91 said:
I tried : the electron move over λu with velocity β so the wavelength is λ≈λu
This is the distance the light can travel while the electrons move by 1 structure length - but then the electrons moved forwards as well. What is the difference between those two distances?
 
the electron moves λu while the light moves λ≈λu /β
so the difference is λu [1/β-1]

so how can I use this fact to find the wave length?

I tried use the approximation β≈1-1q/(2*γ^2) for ultra-relativistic electrons
but still didnt get the right answer...thank you
 
1/β is also 1/(1+β-1) where β-1 is small, so you can express that fraction as ~1-β+1
That should lead to the right answer.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top