Solve Fun Power Question: Frictional Force & Velocity

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The discussion revolves around solving a physics problem involving frictional force and velocity, where the participant attempts to derive an expression for the power required to drive wheels. They start by applying Newton's Second Law and creating a free body diagram, leading to the equation F = 250 + 0.7v^2 + mgsin10. The participant expresses confusion regarding the relationship between acceleration, velocity, and the impact of air resistance, while also noting the need to derive a power expression without specific numerical values. The conversation confirms the correctness of the equations used, emphasizing the importance of understanding the underlying principles rather than just calculating values. Overall, the focus remains on deriving the power expression while grappling with the dynamics of the problem.
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Homework Statement


Found a pretty fun question on power from one of my friends old physics exams just wanted to see if I was doing it right so far.

The Attempt at a Solution


So the first thing I did was draw a free body diagram and used Newtons Second law so

ƩFx: F - (250 + 0.7v^2) - mgsin10 = ma

Says that the driving force F must overcome the frictional force, so then ma = 0 and F = 250 + 0.7v^2 + mgsin10. A little stumped here, I am trying to find out the velocity, but I have two unknowns and one equation (please don't give me the answer, I want to solve it myself)!
 
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Hi Panphobia! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)
Panphobia said:
… ƩFx: F - (250 + 0.7v^2) - mgsin10 = ma

Says that the driving force F must overcome the frictional force, so then ma = 0 and F = 250 + 0.7v^2 + mgsin10. A little stumped here, I am trying to find out the velocity, but I have two unknowns and one equation …

I'm confused … the question says a = 1 and v = 27. :confused:
 
But that is initial, the v is always changing, and in my head I was thinking that there is a maximum velocity because of the air resistance. Oh my was I overthinking that? But anyway I was actually talking about deriving an expression for the power P that is required to drive the wheels. The other part is pretty easy.
 
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Then F = 1150 + 250 + 0.7(27)^2 + (1150)(9.8)sin10
P = Fv
P = 3867.3*27
= 104 kW or 140 hp

Deriving would just be without numbers right?
 
Panphobia said:
Then F = 1150 + 250 + 0.7(27)^2 + (1150)(9.8)sin10
P = Fv
P = 3867.3*27
= 104 kW or 140 hp

(i haven't checked your calculations, but …)

yes, those equations look correct :smile:
Panphobia said:
… I was actually talking about deriving an expression for the power P that is required to drive the wheels.
Deriving would just be without numbers right?

an expression would be without numbers, yes :wink:
 
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